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Tentukan Poh Dan Ph basa Ca(OH)2 0,003

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  • Ca(OH)2 0,003 -> basa kuat
    Ca(OH)2 -> Ca^2+ + 2OH^-
    [OH-] = 2 × 0,003 = 0,006 = 6 × 10^-3
    POH = -log [OH-]
    = -log 6 × 10^-3
    = 3 - log 6
    PH = 14 - POH
    = 14 - (3 - log 6)
    = 11 + log 6

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