Matematika

Pertanyaan

dibantu ya we pliss mohon aku
dibantu ya we pliss mohon aku

1 Jawaban

  • 1.
    [tex] = \frac{ {4}^{5} \times {8}^{2} }{ {16}^{3} } \\ = \frac{{2}^{10} \times {2}^{6} }{ {2}^{12} } \\ = \frac{ {2}^{16} }{ {2}^{12} } \\ = {2}^{4} \\ = 16[/tex]
    2.
    [tex] = ( {2}^{8} \times {4}^{3} )^{2} \\ = ( {2}^{8} \times {2}^{6} )^{2} \\ = ( {2}^{14})^{2} \\ = {2}^{28} [/tex]
    3.
    [tex] = 4 \sqrt{8} + 5 \sqrt{18} - 2 \sqrt{50} \\ = 8 \sqrt{2} + 15 \sqrt{2} - 10 \sqrt{2} \\ = 13 \sqrt{2} [/tex]
    4.
    [tex] = {27}^{ \frac{2}{3} } + \sqrt[3]{64} - {16}^{ \frac{3}{4} } \\ = \sqrt[3]{ {27}^{2} } + 4 - \sqrt[4]{ {16}^{3} } \\ = 9 + 4 - 8 \\ = 5[/tex]
    5.
    [tex] = \frac{8}{2 \sqrt{3} - \sqrt{11} } \\ = \frac{8}{2 \sqrt{3} - \sqrt{11} } \times \frac{2 \sqrt{3} + \sqrt{11} }{2 \sqrt{3} + \sqrt{11} } \\ = \frac{16 \sqrt{3} + 8 \sqrt{11} }{12 - 11} \\ = 16 \sqrt{3} + 8 \sqrt{11} [/tex]


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