dibantu ya we pliss mohon aku
Matematika
matematika502
Pertanyaan
dibantu ya we pliss mohon aku
1 Jawaban
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1. Jawaban AlfandyGulo
1.
[tex] = \frac{ {4}^{5} \times {8}^{2} }{ {16}^{3} } \\ = \frac{{2}^{10} \times {2}^{6} }{ {2}^{12} } \\ = \frac{ {2}^{16} }{ {2}^{12} } \\ = {2}^{4} \\ = 16[/tex]
2.
[tex] = ( {2}^{8} \times {4}^{3} )^{2} \\ = ( {2}^{8} \times {2}^{6} )^{2} \\ = ( {2}^{14})^{2} \\ = {2}^{28} [/tex]
3.
[tex] = 4 \sqrt{8} + 5 \sqrt{18} - 2 \sqrt{50} \\ = 8 \sqrt{2} + 15 \sqrt{2} - 10 \sqrt{2} \\ = 13 \sqrt{2} [/tex]
4.
[tex] = {27}^{ \frac{2}{3} } + \sqrt[3]{64} - {16}^{ \frac{3}{4} } \\ = \sqrt[3]{ {27}^{2} } + 4 - \sqrt[4]{ {16}^{3} } \\ = 9 + 4 - 8 \\ = 5[/tex]
5.
[tex] = \frac{8}{2 \sqrt{3} - \sqrt{11} } \\ = \frac{8}{2 \sqrt{3} - \sqrt{11} } \times \frac{2 \sqrt{3} + \sqrt{11} }{2 \sqrt{3} + \sqrt{11} } \\ = \frac{16 \sqrt{3} + 8 \sqrt{11} }{12 - 11} \\ = 16 \sqrt{3} + 8 \sqrt{11} [/tex]
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