Matematika

Pertanyaan

Nilai dari ³log1/27+⁴log40+⁴log32/5+²log1/8

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  • [tex] {}^{3} log \frac{1}{27} + {}^{4} log40 + {}^{4} log \frac{32}{5} + {}^{2} log \frac{1}{8} \\ {}^{3} log {3}^{ - 3} + {}^{4} log(40 \times \frac{32}{5} ) + {}^{2} log { 2}^{ - 3} \\ - 3 + {}^{4} log(8 \times 32) + - 3 \\ - 6 + {}^{4} log256 \\ - 6 + {}^{4} log {4}^{4} \\ - 6 + 4 = - 2[/tex]

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