hasil 4 1per5 + 5 2per3 : 4per5 = (dgn caranya)

⇔[tex]4 \ \frac{1}{5} + 5 \ \frac{2}{3} \div \ \frac{4}{5} [/tex]

⇔[tex] \frac{21}{5} + \frac{17}{3} \times \frac{5}{4} [/tex]

⇔[tex] \frac{21}{5} + \frac{85}{12} [/tex]

⇔[tex] \frac{677}{60} [/tex]

4 1/5 + 5 2/3 : 4/5 =
21/5 + 17/3 : 4/5 =
21/5 + 17/3 × 5/4 =
21/5 + 85/12 =
252/60 + 425/60 = 677/60 = 11 17/60