Akar2 persamaan kuadrat 3xpangkat2 -x+9=0 adalah x1 dan x2 .nilai x1 perx2 + x2 per x1 adalah

3x² - x + 9 = 0
a = 3
b = -1
c = 9

Dit : x1/x2 + x2/x1

Jawab :

x1 + x2 = -b/a
x1 + x2 = -(-1)/(3)
x1 + x2 = 1/3

x1 . X2 = c/a
x1. x2 = 9/3
x1 . x2 = 3

x1/x2 + x2/x1
= ( (x1)² + (x2)²) / (x1.x2)
= ( (x1 + x2)² - 2x1. x2) / (x1.x2)
= ( (1/3)² - 2(3)) / 3
= ( (1/9) - 6) / 3
= ( 1/9 - 54/9) / 3
= ( -53/9) × 1/3
= -53/27

Nilai x1/x2 + x2/x1 = -53/27