Tolong di bantu soalnya besok di kumpul!!!
Kimia
EkaWD30
Pertanyaan
Tolong di bantu soalnya besok di kumpul!!!
1 Jawaban
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1. Jawaban AgnesAgustine
sin 5pi/3 = sin 5 × 180° / 3
= sin 300° = sin (360°-60°) = - sin 60° = - "akar 3" / 2
tan 7pi/6 = tan 210° = tan (180°+30°) = tan 30° = 1/"akar 3"
sec 2pi = 1/cos 2pi = 1/1 = 1
cos 4pi/3 = cos 240° = cos (180°+60°) = - cos 60° = - 1/2
sin pi/6= sin 30° = 1/2
cos pi/5 = cos 36° = - 0,2
tan pi/4 = tan 45° = 1
2. a) [ -"akar 3"/2 × 1/"akar 3" × 1 ] ÷ 3 × -1/2
= - 1 ÷ - 3/2
= 2/3
2. b) 1/2 + (-0,2) + 1^3
= 1,3