Kimia

Pertanyaan

Tolong di bantu soalnya besok di kumpul!!!
Tolong di bantu soalnya besok di kumpul!!!

1 Jawaban

  • sin 5pi/3 = sin 5 × 180° / 3
    = sin 300° = sin (360°-60°) = - sin 60° = - "akar 3" / 2

    tan 7pi/6 = tan 210° = tan (180°+30°) = tan 30° = 1/"akar 3"

    sec 2pi = 1/cos 2pi = 1/1 = 1

    cos 4pi/3 = cos 240° = cos (180°+60°) = - cos 60° = - 1/2

    sin pi/6= sin 30° = 1/2

    cos pi/5 = cos 36° = - 0,2

    tan pi/4 = tan 45° = 1

    2. a) [ -"akar 3"/2 × 1/"akar 3" × 1 ] ÷ 3 × -1/2
    = - 1 ÷ - 3/2
    = 2/3

    2. b) 1/2 + (-0,2) + 1^3
    = 1,3