Matematika

Pertanyaan

6 akar 8 - 4 akar 32 + akar 128
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2 Jawaban

  • - Bentuk Akar -

    6√8 - 4√32 + √128
    = 6√(4.2) - 4√(16.2) + √(64.2)
    = 12√2 - 16√2 + 8√2
    = 4√2

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    -vin

  • [tex]6 \sqrt{8 } - 4 \sqrt{32 } + \sqrt{128 } \\ 6 \sqrt{4 \times 2} - 4 \sqrt{16 \times 2} + \sqrt{64 \times 2} \\ 6 \times 2\sqrt{2 } - 4 \times 4 \sqrt{2 } + 8 \sqrt{2} \\ 12 \sqrt{2} - 16 \sqrt{2} + 8 \sqrt{2 } \\ 4 \sqrt{2} [/tex]

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