Matematika

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(125)pangkat-(2/3) - (100)pangkat-(3/2)=
Tolong di jawab kk

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  • EksPoneN


    [tex] 125^{ -\frac{2}{3} } - 100^{- \frac{3}{2} } [/tex]
    = [tex] (5³)^{ -\frac{2}{3} } [/tex] - [tex] (10²)^{- \frac{3}{2} } [/tex]
    = [tex] 5^{-2} [/tex] - [tex] 10^{-3} [/tex]
    = 1/5² - 1/10³
    = 1/25 - 1/1000
    = 40/1000 - 1/1000
    = 39/1000

    GoodLuck!

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