Hitunglah PH dari larutan KOH 0,001 M

[OH-] = Xb . Mb
= 1 . 0,001
= 0,001
= 1 x 10^-3

POH = - log [OH-]
= - log 1 x 10^-3
= 3 - log 1
= 3

PH = 14 - POH
= 14 - 3
= 11

semoga membantu:)

[OH-] : b. M
= 1 × 10^-3
= 10^-3

pOH = -log [OH-]
= -log 1×10^-3
= 3-log1
= 3

pH + pOH = 14
pH + 3 = 14
pH = 14 - 3
pH = 11