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Pertanyaan

Hitunglah PH dari Larutan CH3 CooH 0,1 M

2 Jawaban

  • a. [H+]=akar ka.ma
    =akar 10^-5.10^-1
    =akar 10^-6
    =10^-3---> pH=-log[H+]
    =-log10^-3
    =3
    b. [OH-]=b.Mb
    =1.10^-1
    =10^-1

    pOH=-log[OH-]
    =1

    pH=14-pOH
    =14-1
    =13
  • H+ = akar Ka Ma
    H+ = akar 4.10 - 2 x 10-2
    = akar 4.10-4
    = 2.10 - 2 M

    Ph = 2 - log 2

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