Matematika

Pertanyaan

find the missing number in sequence 1,2,3,6,11,20,...., 68??
a. 37 b.38 c. 40 d. 42 e. 44

1 Jawaban

  • u1 = 1
    u2 = 2
    u3 = 3
    u4 = 6
    u5 = 11
    u6 = 20
    u7 = ..
    u8 = 68

    mulai dari u1 = 1
    u2 = u1+u1+u0=2
    u3 = u1+u2+u0=3
    u4 = u1+u2+u3 = 1+2+3 = 6
    u5 = u3+u4+u2 = 11
    u6 = u5+u4+u3 = 11+6+3 = 20
    maka u7 = u6+u5+u4 =20+11+6 = 37 (A) 

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