Tentukan f^-1(7), jika: A) f(x) = 3x-2 B) f(x) = 1/3x + 3

[tex]f(x) = 3x - 2 \\ y = 3x - 2 \\ 3x = y + 2 \\ x = \frac{y + 2}{3} \\ {f}^{ - 1} (x) = \frac{x + 2}{3} \\ {f}^{ - 1} (7) = \frac{7 + 2}{3} \\ {f}^{ - 1} (7) = 3 \\ \\ f(x) = \frac{1}{3}x + 3 \\ y = \frac{x + 9}{3} \\ 3y = x + 9 \\ x = 3y - 9 \\ {f}^{ - 1} (x) = 3x - 9 \\ {f}^{ - 1} (7) = 3(7) - 9 \\ {f}^{ - 1} = 12[/tex]
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