ada yg bisa jawab gak nih ??

[tex]3a + 4 = \sqrt{(3a + 2 ){}^{2} + (a + 4) {}^{2} } \\ 3a + 4 = \sqrt{9a {}^{2} + 12a + 4 + a {}^{2} + 8a + 16} \\ 3a + 4 = \sqrt{10a {}^{2} + 20a + 20} \\\sqrt{10a {}^{2} + 20a + 20} = 3a + 4\\ 10a {}^{2} + 20a + 20 =9a {}^{2} + 24a + 16 \\ 10a {}^{2} - 9a {}^{2} + 20a - 24a + 20 - 16 = 0\\ a {}^{2} - 4a + 4 = 0 \\(a - 2)(a - 2) = 0 \\ a = 2 [/tex]