Diketahui f(x) = 3x-3 g(x)=2-x dan H (x) =x³-1 . Rumus (hogof) invers (x) adalah.. Tolong dibantu, besok harus dikumpulkan.. terimakasih

f(x) = 3x - 3
g(x) = 2 - x
h(x) = x³ - 1
(hogof)(x)
*cari (gof)(x) dulu
(gof)(x) = 2 - (3x - 3)
= 5 - 3x
*masukkan ke (hogof)(x)
(hogof)(x) = (5 - 3x)³ - 1
= 125 - 225x + 135x² - 27x³ - 1
= 124 - 225x + 135x² - 27x³