Matematika

Pertanyaan

akar 50 dikurang akar 8 ditambah akar 18 =

2 Jawaban

  • [tex] = \sqrt{50} - \sqrt{8} + \sqrt{18} \\ = \sqrt{25 \times 2} - \sqrt{4 \times 2} + \sqrt{9 \times 2} \\ = 5 \sqrt{2} - 2 \sqrt{2} + 3 \sqrt{2} \\ = (5 - 2 + 3) \sqrt{2} \\ = 6 \sqrt{2} [/tex]
  • √50-√8+√18
    =√25*2-√4*2+√9*2
    =5√2-2√2+3√2
    =6√2

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