ka tolong dibantu, soal matematika 3log27-2log20-2log2/5+625
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Pertanyaan
ka tolong dibantu, soal matematika
3log27-2log20-2log2/5+625
3log27-2log20-2log2/5+625
1 Jawaban
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1. Jawaban ameldoyenk
³log27 -²log20-²log2/5+625
=3 - ²log20 - ²log2 - ²log5 +625
=3 - ²log20 - 1 - ²log5 + 625
=3 - 1 - (²log20/5) + 625
=2 - ²log4 + 625
=2 - 2 + 625
= 625