1. lim (x² + 5 per x² + 1) X->3 2. Lim (x² - 9 per x + 3) X->-3
Matematika
sumanissa88
Pertanyaan
1. lim (x² + 5 per x² + 1)
X->3
2. Lim (x² - 9 per x + 3)
X->-3
X->3
2. Lim (x² - 9 per x + 3)
X->-3
1 Jawaban
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1. Jawaban mujahair
1. lim (x²+5/x²+1) = 14/10
x→ 3
2. lim(0/0)
x→-3 karena disubtitusikan 0/0 maka difaktorkan
lim [(x-3)(x+3)/(x+3)]
x→ -3
lim (x-3) = -3-3 = -6
x→ -3