tolong bantu ya kk yg F, I, J

[tex]f.) \: \sqrt[4]{5x - 4} - \sqrt[4]{2x + 5} = 0 \\( \sqrt[4]{5x - 4} = \sqrt[4]{2x + 5} \: ) ^{4} \\ 5x - 4 = 2x + 5 \\ 3x = 9 \\ x = 3[/tex]
[tex]i.) \: \sqrt[3]{3x + 6} - \sqrt[3]{9x + 22} = 0 \\( \sqrt[3]{3x + 6} = \sqrt[3]{9x + 22} \: )^{3} \\ 3x + 6 = 9x + 22 \\ - 6x = 16 \\ x = - \frac{16}{6} \\ x = - \frac{8}{3} [/tex]
[tex]j.) \: \sqrt[3]{11x - 5} = \sqrt[3]{8x + 4} \\ (\sqrt[3]{11x - 5} = \sqrt[3]{8x + 4} \: )^{3} \\ 11x - 5 = 8x + 4 \\ 3x = 9 \\ x = 3[/tex]