diketahui f(x) = x² dan g(x)=x+1/2x ;x≠0,maka nilai dari (fog) (2) adalah

f(x) = x²
g(x) = (x+1)/2x

Maka, f o g(x) :
f o g(x) = f(g(x)) = f(x+1/2x)
f o g(x) = (x+1/2x) ²
f o g(x) = (x² + 2x + 1)/4x²

Maka (f o g) (2) :
= (x² + 2x + 1)/4x²
= (2² + 2(2) + 1)/4(2)²
= (4 + 4 + 1)/16
= 9/16

(Fog)(2)
F(x+1/2x)
f(2+1/2.2)
x^2(3/4)
3/4^2
9/16